Optimal. Leaf size=124 \[ -\frac {2 a x}{b^3}+\frac {2 a^2 \left (2 a^2-3 b^2\right ) \tan ^{-1}\left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{b^3 \left (a^2-b^2\right )^{3/2}}-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))} \]
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Rubi [A]
time = 0.16, antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.462, Rules used = {2871, 3102,
2814, 2739, 632, 210} \begin {gather*} \frac {2 a^2 \left (2 a^2-3 b^2\right ) \text {ArcTan}\left (\frac {a \tan \left (\frac {x}{2}\right )+b}{\sqrt {a^2-b^2}}\right )}{b^3 \left (a^2-b^2\right )^{3/2}}-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \sin (x) \cos (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}-\frac {2 a x}{b^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rule 2871
Rule 3102
Rubi steps
\begin {align*} \int \frac {\sin ^3(x)}{(a+b \sin (x))^2} \, dx &=\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}-\frac {\int \frac {a^2-a b \sin (x)-\left (2 a^2-b^2\right ) \sin ^2(x)}{a+b \sin (x)} \, dx}{b \left (a^2-b^2\right )}\\ &=-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}-\frac {\int \frac {a^2 b+2 a \left (a^2-b^2\right ) \sin (x)}{a+b \sin (x)} \, dx}{b^2 \left (a^2-b^2\right )}\\ &=-\frac {2 a x}{b^3}-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}+\frac {\left (a^2 \left (2 a^2-3 b^2\right )\right ) \int \frac {1}{a+b \sin (x)} \, dx}{b^3 \left (a^2-b^2\right )}\\ &=-\frac {2 a x}{b^3}-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}+\frac {\left (2 a^2 \left (2 a^2-3 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {x}{2}\right )\right )}{b^3 \left (a^2-b^2\right )}\\ &=-\frac {2 a x}{b^3}-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}-\frac {\left (4 a^2 \left (2 a^2-3 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {x}{2}\right )\right )}{b^3 \left (a^2-b^2\right )}\\ &=-\frac {2 a x}{b^3}+\frac {2 a^2 \left (2 a^2-3 b^2\right ) \tan ^{-1}\left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{b^3 \left (a^2-b^2\right )^{3/2}}-\frac {\left (2 a^2-b^2\right ) \cos (x)}{b^2 \left (a^2-b^2\right )}+\frac {a^2 \cos (x) \sin (x)}{b \left (a^2-b^2\right ) (a+b \sin (x))}\\ \end {align*}
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Mathematica [A]
time = 0.29, size = 94, normalized size = 0.76 \begin {gather*} \frac {-2 a x+\frac {2 a^2 \left (2 a^2-3 b^2\right ) \tan ^{-1}\left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{\left (a^2-b^2\right )^{3/2}}+b \cos (x) \left (-1-\frac {a^3}{(a-b) (a+b) (a+b \sin (x))}\right )}{b^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.28, size = 142, normalized size = 1.15
method | result | size |
default | \(\frac {4 a^{2} \left (\frac {-\frac {b^{2} \tan \left (\frac {x}{2}\right )}{2 \left (a^{2}-b^{2}\right )}-\frac {a b}{2 \left (a^{2}-b^{2}\right )}}{a \left (\tan ^{2}\left (\frac {x}{2}\right )\right )+2 b \tan \left (\frac {x}{2}\right )+a}+\frac {\left (2 a^{2}-3 b^{2}\right ) \arctan \left (\frac {2 a \tan \left (\frac {x}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \left (a^{2}-b^{2}\right )^{\frac {3}{2}}}\right )}{b^{3}}-\frac {4 \left (\frac {b}{2 \left (\tan ^{2}\left (\frac {x}{2}\right )\right )+2}+a \arctan \left (\tan \left (\frac {x}{2}\right )\right )\right )}{b^{3}}\) | \(142\) |
risch | \(-\frac {2 a x}{b^{3}}-\frac {{\mathrm e}^{i x}}{2 b^{2}}-\frac {{\mathrm e}^{-i x}}{2 b^{2}}+\frac {2 i a^{3} \left (-i a \,{\mathrm e}^{i x}+b \right )}{b^{3} \left (-a^{2}+b^{2}\right ) \left (b \,{\mathrm e}^{2 i x}-b +2 i a \,{\mathrm e}^{i x}\right )}+\frac {2 i a^{4} \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{\sqrt {a^{2}-b^{2}}\, b}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right ) \left (a -b \right ) b^{3}}-\frac {3 i a^{2} \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{\sqrt {a^{2}-b^{2}}\, b}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right ) \left (a -b \right ) b}-\frac {2 i a^{4} \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{\sqrt {a^{2}-b^{2}}\, b}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right ) \left (a -b \right ) b^{3}}+\frac {3 i a^{2} \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{\sqrt {a^{2}-b^{2}}\, b}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right ) \left (a -b \right ) b}\) | \(394\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 483, normalized size = 3.90 \begin {gather*} \left [-\frac {{\left (2 \, a^{5} - 3 \, a^{3} b^{2} + {\left (2 \, a^{4} b - 3 \, a^{2} b^{3}\right )} \sin \left (x\right )\right )} \sqrt {-a^{2} + b^{2}} \log \left (\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2} + 2 \, {\left (a \cos \left (x\right ) \sin \left (x\right ) + b \cos \left (x\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2}}\right ) + 4 \, {\left (a^{6} - 2 \, a^{4} b^{2} + a^{2} b^{4}\right )} x + 2 \, {\left (2 \, a^{5} b - 3 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (x\right ) + 2 \, {\left (2 \, {\left (a^{5} b - 2 \, a^{3} b^{3} + a b^{5}\right )} x + {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (x\right )\right )} \sin \left (x\right )}{2 \, {\left (a^{5} b^{3} - 2 \, a^{3} b^{5} + a b^{7} + {\left (a^{4} b^{4} - 2 \, a^{2} b^{6} + b^{8}\right )} \sin \left (x\right )\right )}}, -\frac {{\left (2 \, a^{5} - 3 \, a^{3} b^{2} + {\left (2 \, a^{4} b - 3 \, a^{2} b^{3}\right )} \sin \left (x\right )\right )} \sqrt {a^{2} - b^{2}} \arctan \left (-\frac {a \sin \left (x\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (x\right )}\right ) + 2 \, {\left (a^{6} - 2 \, a^{4} b^{2} + a^{2} b^{4}\right )} x + {\left (2 \, a^{5} b - 3 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (x\right ) + {\left (2 \, {\left (a^{5} b - 2 \, a^{3} b^{3} + a b^{5}\right )} x + {\left (a^{4} b^{2} - 2 \, a^{2} b^{4} + b^{6}\right )} \cos \left (x\right )\right )} \sin \left (x\right )}{a^{5} b^{3} - 2 \, a^{3} b^{5} + a b^{7} + {\left (a^{4} b^{4} - 2 \, a^{2} b^{6} + b^{8}\right )} \sin \left (x\right )}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.45, size = 204, normalized size = 1.65 \begin {gather*} \frac {2 \, {\left (2 \, a^{4} - 3 \, a^{2} b^{2}\right )} {\left (\pi \left \lfloor \frac {x}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, x\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{{\left (a^{2} b^{3} - b^{5}\right )} \sqrt {a^{2} - b^{2}}} - \frac {2 \, {\left (a^{2} b \tan \left (\frac {1}{2} \, x\right )^{3} + 2 \, a^{3} \tan \left (\frac {1}{2} \, x\right )^{2} - a b^{2} \tan \left (\frac {1}{2} \, x\right )^{2} + 3 \, a^{2} b \tan \left (\frac {1}{2} \, x\right ) - 2 \, b^{3} \tan \left (\frac {1}{2} \, x\right ) + 2 \, a^{3} - a b^{2}\right )}}{{\left (a \tan \left (\frac {1}{2} \, x\right )^{4} + 2 \, b \tan \left (\frac {1}{2} \, x\right )^{3} + 2 \, a \tan \left (\frac {1}{2} \, x\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, x\right ) + a\right )} {\left (a^{2} b^{2} - b^{4}\right )}} - \frac {2 \, a x}{b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 9.98, size = 2578, normalized size = 20.79 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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